Ayakatoyotazj7

Simplify X 3 2x 1 X X 5 2 x 1 4 x 3 x 2 x 1 + 5 x 4 x 3 x 2 x 1

 5 * 1 6 z = 5 5 6 z = 5 Subtract 5 to both sides 5 6 z 5 = 5 5 6 z = 0 Divide both sides by 6 z = 0 Replace y = 1 and z = 0 in equation 2 x 3 y 3 z = 5 2 x 3 y 3 z = 5 2 x 3 * 1 3 * 0 = 5 2 x 3 0 = 5 Explanation You know the value of the variable x, so you can substitute that into the equation x (3y − 1) 2y = 9 Remove the parentheses and solve 3y −1 2y = 9 ⇒ 5y − 1 = 9 ⇒ 5y = 10 ⇒ y = 2 Plug y into either equation to find x1 2 3\pi e x^{\square} 0 \bold{=} Go Related » Graph » Number Line » Examples » Our online expert tutors can answer this problem 3x^2=y, x1=y en Related Symbolab blog posts High School Math Solutions – Systems of Equations Calculator, Elimination Please try again using a different payment method Subscribe to get Maths Class 10 Pages 51 100 Flip Pdf Download Fliphtml5 3/x-1/y 9=0 2/x 3/y=5 by substitution method